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The 1 H NMR spectrum of the product revealed a peak in the alkene range at 6.30 ppm, H-2 and H-3 (Figure 1). In addition, it exhibited two peaks at 3.57 and 3.45 ppm because of the proximity of H-1, H-4, H-5, and H-6 to an electronegative atom, oxygen 3
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Because only 1.1% of carbon in a compound is 13 C, 13 C- 13 C coupling is negligible and thus is not observed. Therefore, in one type of 13 C NMR Spectra( proton decoupled) each magnetically non equivalent carbon gives a single unsplit peak
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1. Why carbon forms strong bonds with other Carbon atoms,Hydrogen,Oxygen,Nitrogen and Sulphur? 2. Name the part of eye responsible for conversion of light into electrical impulses. 3. (a) How does valency vary in a group on going from top to bottom? (b) 4.
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